Question 878141
{{{5^(2x+1)=2^x}}}
{{{log((5^(2x+1)))=log((2^x))}}}
{{{(2x+1)*log((5))=x*log((2))}}}
Substitute to make it easier to read,
{{{(2x+1)a=bx}}}
{{{2ax+a=bx}}}
{{{(2a-b)x=-a}}}
{{{x=(-a)/(2a-b)}}}
{{{x=a/(b-2a)}}}
{{{highlight(x=log((5))/(log((2))-2*log((5))))}}}