Question 878202
0.3y^2+0.15y-11.7=0 the quadratic formula is
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} plug in your values into the formula
{{{x = (-0.15 +- sqrt( 0.15^2-4*0.3*(-11.7) ))/(2*0.3) }}} simplify 
{{{x = (-0.15 +- sqrt( 0.0225+14.04 ))/(0.6) }}} simplify
{{{x = (-0.15 +- sqrt( 14.0625 ))/(0.6) }}} simplify
{{{x = (-0.15 +- 3.75)/(0.6) }}}
case 1
{{{x = (-0.15 + 3.75)/(0.6) }}} evaluate
{{{x = (3.6)/(0.6) }}}
{{{x = 6 }}}
case 2
{{{x = (-0.15 - 3.75)/(0.6) }}} evaluate
{{{x = (-3.9)/(0.6) }}}
{{{x = 6.5 }}}