Question 878075
sketch the hyperbola (vertical or horizontal?) 
(x+1)^2/16+(y-2)^2/64=1
This is an equation of an ellipse, not a hyperbola
see graph below:
y=±(64-4(x+1)^2)^.5+2
{{{ graph( 300, 300, -10, 10, -10, 10, (64-4(x+1)^2)^.5+2,-(64-4(x+1)^2)^.5+2) }}}