Question 878007
{{{y=KC^x}}}
{{{log((y))=log((KC^x))}}}
{{{log((y))=log((K))+log((C^x))}}}
{{{log((y))=log((K))+x*log((C))}}}
{{{w=mx+b}}}
Now it looks like a linear equation where the slope of the line is equal to {{{log((C))}}} and the w-intercept is equal to {{{log((K))}}}. 
Plot the log of results and draw the best fit line.
Determine the slope and intercept.
Then you will have K and C.