Question 877977
{{{4^(3x-2) = 22^x}}}


{{{log((4^(3x-2)))=log((22^x))}}}
{{{(3x-2)log((4))=x*log((22))}}}
{{{3x*log((4))-2*log((4))=x*log((22))}}}
{{{3x*log((4))-x*log((22))=2*log((4))}}}
{{{x(3*log((4))-log((22)))=2*log((4))}}}


{{{highlight(x=(2*log((4)))/(3*log((4))-log((22))))}}}
Decide what base you want and then compute.