Question 877926
Let {{{ a }}} = Lea's age now
Let {{{ b }}} = Cherry's age now
---------------------------
{{{ a + 5 }}} = Lea's age in 5 yrs
{{{ b + 5 }}} = Cherry's age in 5 yrs
------------------------------
(1) {{{ a = 6b + 5 }}}
(2) {{{ a + 5 = 4*( b + 5 ) }}}
-------------------------
(1) {{{ a - 6b = 5 }}}
and
(2) {{{ a + 5 = 4b + 20 }}}
(2) {{{ a - 4b = 15 }}}
-------------------
Subtract (1) from (2)
(2) {{{ a - 4b = 15 }}}
(1) {{{ -a + 6b = -5 }}}
{{{ 2b = 10 }}}
{{{ b = 5 }}}
and
(1) {{{ a = 6b + 5 }}}
(1) {{{ a = 6*5 + 5 }}}
(1) {{{ a = 35 }}}
--------------
Lea is 35 and Cherry is 5
check:
(2) {{{ a + 5 = 4*( b + 5 ) }}}
(2) {{{ 35 + 5 = 4*( 5 + 5 ) }}}
(2) {{{ 40 = 40 }}}
OK