Question 73947
Solve for x:
{{{3x^2-5x = 8}}} First, subtract 8 from both sides of the equation.
{{{3x^2-5x-8 = 0}}} Now factor this trinomial.
{{{(3x-8)(x+1) = 0}}} Apply the zero product principle.
{{{3x-8 = 0}}} and/or {{{x+1 = 0}}}
{{{3x-8 = 0}}} Add 8 to both sides.
{{{3x = 8}}} Divide both sides by 3.
{{{x = 8/3}}} or {{{x = 2.7}}}  This is one of the roots.
{{{x+1 = 0}}} Subtract 1 from both sides.
{{{x = -1}}} This is the other root.