Question 877293
{{{G=(t/(3.3log(F/b)))}}} where  G=16, F=256, b=2

{{{16=(t/(3.3log(256/2)))}}}
{{{16=(t/(3.3log(128)))}}}
{{{t=16(3.3log(128))}}}
{{{t=111.26}}}

It will take 2 bacteria 111.26 hours to multiply into 256