Question 877594
I'm assuming the equation is {{{e^(2z-1) = 3}}}



Use natural logs to isolate the exponent and then solve for z



{{{e^(2z-1) = 3}}}



{{{ln(e^(2z-1)) = ln(3)}}}



{{{(2z-1)ln(e) = ln(3)}}}



{{{(2z-1)*1 = ln(3)}}}



{{{2z-1 = ln(3)}}}



{{{2z = ln(3)+1}}}



{{{z = (ln(3)+1)/2}}} <font color="red"><--- Exact Answer</font>



{{{z = 1.04930614433406}}} <font color="blue"><--- Approximate Answer</font> (use a calculator to evaluate, be sure to round appropriately if needed)