Question 877534
Assuming {{{a>=0}}}



{{{sqrt(2a)*sqrt(8a)}}}



{{{sqrt(2a*8a)}}}



{{{sqrt(2*8*a*a)}}}



{{{sqrt(16a^2)}}}



{{{sqrt((4a)^2)}}}



{{{4a}}}



So, {{{sqrt(2a)*sqrt(8a)}}} simplifies to {{{4a}}}. This is assuming {{{a>=0}}}