Question 877350
If sin Θ = 5 over 6, what are the values of cos Θ and tan Θ
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sin Θ=5/6 
sin^2Θ+cos^2Θ=1
cos Θ=√(1-sin^2Θ)=√(1-25/36)=√(11/36)=√11/6
tan Θ=sin Θ/cos Θ=5/√11=5√11/11