Question 877202
The velocity v (m/s) of a body t seconds after a certain instant is given by the equation below.
Using definite integration determine the total distance moved after 10 seconds, given that at time t=0 the distance is also 0 if:
v=2t^3-3t^2+2t+7
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{{{INT(t) = t^4/2 - t^3 + t^2 + 7t + C}}}
--> C = 0
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INT(10) = 5000 - 1000 + 100 + 70 = 4170
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The distance is from (0,0) to (10,4170)
Do you know how to find the distance along the function?