Question 73804
help divide these fractions
4x^2/x^2 - 25 divided 2x/x^2 + 2x - 15
:
{{{4x^2/((x^2 - 25))}}} divided {{{2x/((x^2 + 2x - 15))}}}
:
Remember when you divide, you invert the dividing fraction and multiply:
{{{4x^2/((x^2 - 25))}}} * {{{((x^2 + 2x - 15))/(2x)}}}
:
do some factoring:
{{{4x^2/((x-5)(x+5)))}}} * {{{((x+5)(x-3))/(2x)}}}
:
Do some canceling and we have:
{{{2x/((x-5)))}}} * (x-3) = {{{(2x(x-3))/((x-5)))}}} = {{{((2x^2-6x))/((x-5)))}}}