Question 877032
Let the 4 numbers be
{{{ a }}}, {{{ b }}}, {{{ c }}}, and {{{ d }}}
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(1) {{{ a + b + c + d = 95 }}}
(2) {{{ b = 2a }}}
(3) {{{ c = 3a }}}
(4) {{{ d = a + 25 }}}
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Substitute (2), (3), and (4) into (1)
(1) {{{ a + 2a + 3a + a + 25 = 95 }}}
(1) {{{ 7a = 95 - 25 }}}
(1) {{{ 7a = 70 }}}
(1) {{{ a = 10 }}}
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(2) {{{ b = 2a }}}
(2) {{{ b = 2*10 }}}
(2) {{{ b = 20 }}}
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(3) {{{ c = 3a }}}
(3) {{{ c = 3*10 }}}
(3) {{{ c = 30 }}}
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(4) {{{ d = a + 25 }}}
(4) {{{ d = 10 + 25 }}}
(4) {{{ d = 35 }}}
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The four numbers are 10, 20, 30, and 35
check:
(1) {{{ a + b + c + d = 95 }}}
(1) {{{ 10 + 20 + 30 + 35 = 95 }}}
(1) {{{ 95 = 95 }}}
OK