Question 876082
How do I find the y intercept, x intercept, range, and domain of the following function: 
f(x)=log(2)(3-x)+2 (the (2) is a base)
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f(x)={{{(log(3-x)/log(2))+2}}}
y-intercept
set x=0
{{{log(3)/log(2)+2=3.585}}}
...
x-intercept
set y=0
0={{{(log((3-x))/log(2))+2}}}
{{{(log((3-x))/log(2))=-2}}}
-2log(2)=log(3-x)
log(2^-2)=log(3-x)
log(1/2^2)=log(3-x)
log(1/4)=log(3-x)
1/4=3-x
x=11/4
range:(-∞,∞)
domain(-∞,3)