Question 876872
log(x)+log(x-3)=log(108)
log(x*(x-3)) = log(108)
x*(x-3) = 108
x^2 - 3x = 108
x^2 - 3x - 108 = 0
(x - 12)(x + 9) = 0
 x = 12 or x = -9