Question 876801
Let's say we have these 8 people: A,B,C,D,E,F,G,H


Let A and B be the husband and wife. Consider them as one person. Call this "person" Z


So we now have this group  Z,C,D,E,F,G,H


"Person" Z has to be in the middle, so let's force Z to be in slot 4 to get C,D,E,Z,F,G,H



Z is locked in slot 4 and cannot move. There are 7-1 = 6 other slots. So there are 6! = 6*5*4*3*2*1 = 720 ways to arrange them.


Because we can arrange the husband and wife to be on either side of each other (to have AB or BA) we need to double 720 to get 2*720 = 1,440



So there are <font color="red">1,440</font> ways to seat this group of 8 people.