Question 876714
{{{log(7,n)=(2/3)log(7,8)}}}
{{{log(7,n)=log(7,8^(2/3))}}}
{{{log(7,n)=log(7,(2^3)^(2/3))}}}
{{{log(7,n)=log(7,(2^2))}}}
{{{log(7,n)=log(7,(4))}}}
{{{n=4}}}