Question 73701
You got it ... there's an easy way once you think about it a little.  But before that, there are
25 prime numbers between 1 and 100.  They are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41,
43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.
.
Let's look at the product of just two of these primes.  The product of 2 and 5 is, of course,
10.  After that, what is the units digit of any other multiplication?  10 * 3 = 30. That times
7 is 210. Times 11 is 2310.  There we have the product of the first 5 primes. And by now you
can probably see that any additional multiplications will end in zero in the units position (even if you go to the product of the primes out to a million or beyond).
.
Does this help?  Hope so ...