Question 876466
Complete the square to get to vertex form,
{{{3x^2 - 12x - y + 18 = 0}}}

{{{y=3x^2-12x+ 18}}}
{{{y=3(x^2-4x)+ 18}}}
{{{y=3(x^2-4x+4)+ 18-3*4}}}
{{{y=3(x-2)^2+6}}}
(3,6)
Since {{{3>0}}}, parabola opens up.
{{{graph(300,300,-2,10,-2,10,3(x-2)^2+6)}}}