Question 876529
Let the number be xy

10x+y+10y+x=99

11x+11y=99
/11
x+y=9.....................(1)

ii condition

10x+y+5 = 6(x+y)-4

10x+y+5=6x+6y-4

4x-5y=-9..................(2)

solve (1) &(2)

1	x	+	1	y	=	9	.............1	
								
4	x		-5	y	=	-9	.............2	
-5	y							
multiply (1)by		5						
Multiply (2) by		1						
5	x		5	y	=	45		
4	x		-5	y	=	-9		
Add the two equations								
9	x				=	36		
/	9							
x	=	4      						
plug value of			x	in (1)				
1	x	+	1	y	=	9		
4		+		y	=	9		
				y	=	9		-4
				y	=	5		
				y	=	5		
the number is 45