Question 876455
"An old water pipe is to be replaced by a new one so that twice as much water can flow through the pipe. What is the ratio of the radius of the new pipe to that of the old pipe?"
---------------
Assuming 2x the flow rate --> 2x the area:
{{{Area = pi*r^2}}}
{{{2*Area = pi*(k*r)^2 = pi*k^2*r^2}}} k = some number
{{{k^2 = 2}}}
{{{k = sqrt(2)}}}
r of new pipe = {{{sqrt(2)}}}*r of the old pipe