Question 876359
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}} 
where Pt(h,k) is the center and r is the radius
{{{(x-6)^2 + (y-0)^2 = 6^2}}} radius must be 6 IF circle passes thru (0,0)