Question 876266
t ={{{2/sqrt((2.7386/5)+(2/5))}}} = 2.0544 for A &  B , B & C Comparisons
t ={{{4/sqrt((2.7386/5)+(2/5))}}} = 4.10885 for A &  C Comparisons
p-value = 2*P(t> 2.0544 when df = 4) = 2(.0546) = .1092
p-value = 2*P(t> 4.1089when df = 4) = 2(.0074) = = .0148
.0148 < .05 
A&C comparison significantly says populations mean are NOT equal.
Recommend vassarstats.net/anova to check Your work