<PRE><B>Question 875750</B>
&quot;angle A is twice the sum of angles B and C&quot; so A = 2*(B+C)



Since B = 24, we know



A = 2*(B+C)



A = 2*(24+C)



A = 2*24+2C



A = 48 + 2C



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All 3 angles add to 180 degrees, so A+B+C = 180



A+B+C = 180



A+24+C = 180 ... plug in B = 24



48+2C+24+C = 180 ... plug in A = 48+2C, now solve for C



48+2C+24+C = 180



72+3C = 180



3C = 180-72



3C = 108



C = 108/3



C = 36



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Use this to find A



A = 48+2C



A = 48+2*36 ... plug in C = 36



A = 48+72



A = 120</PRE>