Question 73859
3b+2c=46
5c+b=11
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"linear combination" means you should solve the system by adding
or subtracting the equations.
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You have:
3b+2c=46
b +5c=11
You want to eliminatie one of the variables by adding or subtracting.
You could multiply the 2nd equation by 3 to get:
3b+15c=33
Then subtract that from the 1st equation to get:
-13c = 13
c=-1
Now you can solve for b by substituting that value into one of the original equations.
b + 5(-1) = 11
b=16
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The system solution is c=-1 ; b=16
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Cheers,
Stan H.