Question 875567
Given that sinӨ = 0.2419 and that Ө is in quadrant I, find sin [Ө/2]
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Use half-angle formula for sin: {{{sin(x/2)=sqrt((1-cosx)/2)}}}
{{{cos(theta)=sqrt(1-sin^2(theta))=sqrt(1-.2419^2)=sqrt(0.9415)=.9703}}}
{{{sin(theta/2)=sqrt((1-cos(theta))/2)=sqrt((1-.9703)/2)=sqrt(.0149)=0.122}}}
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Calculator check:
sin &#1256=.2419
&#1256=13.9987˚
&#1256/2=6.9993˚
sin&#1256/2=0.122