Question 73710
(7^x-3)/(7^3x+1)=1
I think you mean:
{{{7^(x-3)/7^(3x+1)}}} = 1
:
Just looking at it you have to say:
3x + 1 = x - 3
3x - x = -3 - 1
2x = -4
x = -2
:
:
Check:
{{{7^(-2-3)/7^(3(-2)+1)}}} = 1
{{{7^(-2-3)/7^(-6+1)}}} = 1