Question 875315
(1) {{{ q = d + 6 }}}
(2) {{{ n = 4q }}}
(3) {{{ 5n + 10d + 25q = 380 }}}
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(1) {{{ d = q - 6 }}}
Substitute (1) and (2) into (3)
(3) {{{ 5*( 4q ) + 10*( q - 6 ) + 25q = 380 }}}
(3) {{{ 20q + 10q - 60 + 25q = 380 }}}
(3) {{{ 55q = 440 }}}
(3) {{{ q = 8 }}}
and
(2) {{{ n = 4q }}}
(2) {{{ n = 4*8 }}}
(2) {{{ n = 32 }}}
and
(1) {{{ d = q - 6 }}}
(1) {{{ d = 8 - 6 }}}
(1) {{{ d = 2 }}}
He has 32 nickels, 2 dimes, and 8 quarters
check:
(3) {{{ 5n + 10d + 25q = 380 }}}
(3) {{{ 5*32 + 10*2 + 25*8 = 380 }}}
(3) {{{ 160 + 20 + 200 = 380 }}}
(3) {{{ 380 = 380 }}}
OK