Question 875193
16^(-1/4) = {{{ 1/root(4,16)}}} = 1/2
{{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}}
{{{root(a,p)*root(a,q) = root(a,p*q)}}}  
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
{{{root(n, (x/y)) = root(n,x)/root(n,y)}}}
{{{(xy)^n = x^n*y^n}}}
{{{x^(1/n) = root(n,x)}}}   Applied