Question 875033
L length
w width
L....what if the situation were,
The length of a rectangle is k cm more than m times its width. If the perimeter of the rectangle is p cm, what are its dimensions?


{{{L=mw+k}}} and {{{2w+2L=p}}}.
You KNOW that p is even, so say {{{w+L=p/2}}}.
{{{w+mw+k=p/2}}}
{{{w+mw=p/2-k}}}
{{{w(1+m)=p/2-k}}}
{{{w(2+m)=p/2-2k/2=(p-2k)/2}}}
{{{w=(p-2k)/(2(2+m))}}}
{{{highlight(w=(p-2k)/(2m+4))}}}.
Use this w to solve or evaluate {{{highlight(L=mw+k)}}}.