Question 875093
Using knowledge of Standard Form of a linear equation, the known second equation has slope {{{2/3}}}.  A line perpendicular to the equation has a slope {{{-3/2}}}.


Wanting the first equation to be perpendicular to the second known equation, you want {{{-A/2=-3/2}}};
{{{A/2=3/2}}}
{{{highlight(A=3)}}}.


The second Question:
{{{3(3x+2y)+2(2x-3y)=3*1+2*(-5)}}}, a start for Elimination Method.
{{{13x=-7}}}
{{{highlight(x=-7/13)}}}.   
-
{{{2y=1-3x}}}
{{{y=1/2-3x/2}}}
{{{y=1/2+3(7/13)/2}}}
{{{y=1/2+21/26=13/26+21/26=34/26=17/13}}}
{{{highlight(y=17/13)}}}.