Question 875044
That's a nice way of putting the description.


With enough experience you may quickly form this:
{{{highlight_green((10x+30y)/500=20)}}} and {{{highlight_green(x+y=500)}}}.
Solve for x and y.


See a complete lesson on this here: <a href="http://www.algebra.com/tutors/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev">Mixing two concentrations for known amount of mixture </a>