Question 874821
The solution provided by the other tutor is correct but incomplete. The end should be:
2x = 30 + 360n
2x = 330 + 360n
Dividing by 2:
x = 15 + 180n
x = 165 + 180n
Trying various integers for n, looking for x's between 0 and 360, we get:
x = 30 (when n = 0 in the first equation)
x = 210 (when n = 1 in the first equation)
x = 165 (when n = 0 in the second equation)
x = 345 (when n = 1 in the second equation)
Other n's result in x's that are either below 0 or above 360. So the solutions are 30, 165, 210 and 345.