Question 874821
Solve: cos^2 theta - sin^2 theta = rad3/2 for theta in the domain [0deg, 360deg]
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{{{cos^2(x)-sin^2(x)=sqrt(3)/2}}}
{{{cos(2x)=sqrt(3)/2}}}
2x=30&#730;, 330&#730;
x=15&#730;, 165&#730;