Question 874768
Tan (&#960;/6) = &#8730;3/3 and Tan (7&#960;/6) = &#8730;3/3  Interval 0 to 2&#960;
sec(&#960;/6) = 1/cos(&#960;/6) = 1/(&#8730;3/2) = 2/&#8730;3 0r 2&#8730;3/3
sec(7&#960;/6) = 1/cos(7&#960;/6) = 1/-(&#8730;3/2) = -2/&#8730;3  0r -2&#8730;3/3
below (cosx, sinx) Summary
<img src='http://img9.imageshack.us/img9/2032/mfpe.png'border='0'/></a>