Question 73714
{{{((z+3))/((z+5))}}} = {{{((z-2))/((z-5))}}}
:
Cross multiply and you have:
z^2 + 3z - 10 = z^2 - 2z - 15
:
z^2 - z^2 + 3z + 2z = -15 + 10; z's on the left, numbers on the right
:
5z = -5
:
z = -1
:
:
Check:
{{{((-1+3))/((-1+5))}}} = {{{((-1-2))/((-1-5))}}}
{{{((2))/((4))}}} = {{{((-3))/((-6))}}}