Question 874719
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Hi
p = .75 , n = 5
P(x &#8805;  4) = P(4)+P(5)  0r = 1 - binompdf(5, .75,3)= .6328

Using {{{P (x)= highlight_green(nCx)(p^x)(q)^(n-x) }}} 
p and q are the probabilities of success and failure respectively. 
In this case p= .75, q = .25  and n = 5
{{{nCx = (n!)/x!(n - x)!)}}} 
P(4)+P(5) = 5C4(.75)^4(.25)^1 + 5C5(.75)^5(.25)^0