Question 874572
{{{ x^2-2x-3= sqrt( 4 ) }}}


{{{x^2-2x-3= 2}}}


{{{x^2-2x-3-2=2-2}}}


{{{x^2-2x-5=0}}}


Now that we have the equation set to zero, we can use the quadratic formula.


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


*[invoke quadratic "x", 1, -2, -3 ]