Question 874406
Given cos x  = - 1/5 and tan x  > 0, find sin x
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ABS {{{sin(x) = sqrt(1 - cos^2(x)) = sqrt(24/25) = 2sqrt(6)/5}}}
cos < 0 --> Q2 or Q3
tan > 0 --> Q1 or Q3
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--> Q3
In Q3 sin < 0
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{{{sin(x) = -2sqrt(6)/5}}}