Question 874336
please help me solve this equation log3X + log3(x+2) = 1 solve for x
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I'm assuming you meant log base 3:
{{{log(3,X) + log(3,x+2) = 1}}}
{{{log(3,X(x+2)) = 1}}}
{{{x(x+2) = 3^1}}}
{{{x^2+2x = 3}}}
{{{x^2+2x-3=0}}}
{{{(x+3)(x-1)=0}}}
x = {-3, 1}
Throw out the -3 solution (extraneous) leaving
x = 1