Question 874202
A triangle has a side of length of x.
The second side of the triangle is 2 inches longer than the first side.
x+2
The third side is 4 inches longer than the first side.
x+4
The square of the first side plus the square of the second side is equal to the square of the third side.
x^2+(x+2)^=(x+4)^2
What is the length of each side of the triangle.

x^2+x^2+4x+4=x^2+8x+16

x^2-4x-12=0

x^2-6x+2x-12=0

x(x-6)+2(x-6)=0
(x-6)(x+2)=0

x=6 
ignore negative

6,8,10 are the sides