Question 874223
sin(pi-x)+cos(pi-x)=sin(x)-cos(x)



sin(pi)cos(x)-cos(pi)sin(x)+cos(pi)cos(x)+sin(pi)sin(x)=sin(x)-cos(x)



0*cos(x)-(-1)*sin(x)+(-1)*cos(x)+0*sin(x)=sin(x)-cos(x)



0+sin(x)-cos(x)+0=sin(x)-cos(x)



sin(x)-cos(x)=sin(x)-cos(x)



The identity is verified.