Question 874033
1.{{{x^2+y^2=17}}}
2.{{{x-4y=0}}}
From eq. 2,
{{{x=4y}}}
Substitute into eq. 1,
{{{(4y)^2+y^2=17}}}
{{{16y^2+y^2=17}}}
{{{17y^2=17}}}
{{{y^2=1}}}
{{{y=0 +- 1}}}
When {{{y=1}}}, {{{x=4}}}
When {{{y=-1}}},{{{x=-4}}}
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{{{drawing(300,300,-6,6,-6,6,grid(1),
circle(4,1,0.25),
circle(-4,-1,0.25),
circle(0,0,sqrt(17)),
graph(300,300,-6,6,-6,6,x/4))}}}