Question 874019
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Hi
x+y=-2  0r y ={{{-x-2}}}
(x+3)^2+(y+2)^2=17
(x+3)^2+(-x)^2=17
2x^2 + 6x - 8 = 0
 x^2 + 3x - 4 = 0
 (x+4)(x-1) = 0, x = -4,1
(-4, 2) and (1, -3) are the solutions for this System