Question 874010
 <pre><font face = "consolas" color = "indigo" size = 3><b>
Hi
ln (8x^2) - 2 ln(2x)  =ln (8x^2) - ln(2x)^2 = ln(8x^2/4x^2) = ln 2  
*[tex \large\ \ nlog_bx = log_b(x^n) ]  Applied
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ] Applied
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ ln e^x = x]
{{{ e^(lnx) = x}}}
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]