Question 873917
If "Six apples and 1 pear cost $2.00", then {{{6a+1p = 2}}} where 'a' is the cost for a single apple and p is the cost for a single pear.


If "3 apples and 6 pears cost $2.10", then {{{3a+6p = 2.10}}}


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The two equations you'll use are


{{{6a+1p = 2}}}
{{{3a+6p = 2.10}}}



Solve for p in {{{6a+1p = 2}}} to get {{{p = 2-6a}}}


Then plug this into the second equation to get 


{{{3a+6p = 2.10}}}


{{{3a+6(2-6a) = 2.10}}}



Solving that equation for 'a' will give you the cost for a single apple. Once you know the value of 'a', plug it into {{{p = 2-6a}}} to find the value of p (the cost for a single pear)