Question 873471
find the standard form of the equation of the specified hyperbola
vertices: (0,2)and (0,-2)
foci: (0,4)and(0,-4)
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Given data shows that hyperbola has a vertical transverse axis.
Its standard form of equation: {{{(y-k)^2/a^2-(x-h)^2/b^2=1}}}, (h,k)=coordinates of center
center: (0,0)
a=2
a^2=4
c=4
c^2=16
c^2=a^2+b^2
b^2=c^2-a^2=16-4=12
equation: {{{y^2/4-x^2/12=1}}}