Question 73734
Using the difference of cubes forumla:
{{{m^3-n^3 = (m-n)(m^2+mn+n^2)}}}
We can see that m=x and n=4 (since 4^3=64) So a=-n,b=n, and c=n^2. Since n=4, a=-4, b=4, and c=16 (just match the variables). So the answer is [-4,4,16].