Question 873405
To find 3 numbers, you need three equations. 
{{{a+b+c=118}}}
{{{a+2b+c=135}}}
Subtract eq. 1 from eq. 2,
{{{a+2b+c-a-b-c=135-118}}}
{{{b=17}}}
So that leaves you with 
{{{a+c=101}}} 
So you can get one variable in terms of another.
{{{c=101-a}}}
Then your solution would look like,
({{{a}}},{{{17}}},{{{101-a}}}) for any value {{{a}}}.